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This equation can be written as where are direction ratios.

Here, .

Hence, direction cosines are .

Here, .

Hence, direction cosines are .

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take a point P on the straight line L x = 2 y = 5 z.

Take x = 10 (lcm of 2 and 5) y = 5 and z = 2. P = (10, 5 , 2)

this straight line L goes through the origin O.

the distance OP = r = √(10²+5²+2²) = √129

Direction cosines are (cos α, cos β, cos γ) = ( x/r , y/r, z/r )

= ( 10/√129, 5/√129, 2/√129)

Take x = 10 (lcm of 2 and 5) y = 5 and z = 2. P = (10, 5 , 2)

this straight line L goes through the origin O.

the distance OP = r = √(10²+5²+2²) = √129

Direction cosines are (cos α, cos β, cos γ) = ( x/r , y/r, z/r )

= ( 10/√129, 5/√129, 2/√129)