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A hollow sphere of external and internal diameters of 8 cm and 4 cm respectively is melted and made into another solid in the shape of a right circular

cone of base diameter of 8 cm. find the height of the cone.


Volume of the hollow sphere, V(s) = (4/3)π(4³-2³) = (4/3)π(56).
Now, this becomes the volume of cone, V(c) = (1/3)π(4²)h = (4/3)π(56).
Then height of the cone, h = 14cm.
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Volume of substance in the sphere = 4/3* π (4³ - 2³) = 224 /3 * π  cm³

volume of right circular cone = 1/3 *π R² H  = 224 /3 * π
       R of base of cone =  4 cm
         H = 224 / 4² = 14 cm

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