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Find the position of an object , which when placed in front of a concave mirror of focal length 10cm produces a virtual image , which is twice the size of

Here, h'=2h where h is the object height and h' is the image height. we know that, m=h'/h but h'=2h or h'/h=2 so,m(magnification)=2 we know that m=h'/h=-v/u where v is the image distance and u is the object distance. so, m=-v/u or, 2=-v/u or, 2u=(-v)..............................(eq.1) by mirror formula, 1/f=1/v+1/u or, 1/v+1/u=1/f 1/v=1/f-1/u 1/v=u-f/fu or, v=fu/u-f =u(-10)/u-(-10) therefore, v =(-10u)/u+10.......................(eq.2) From eq.1, 2u=(-v) 2u=-[-10u/u+10] =10u/u+10 2u=10u/u+10 or, 2u(u+10)=10u or, u+10=10u/2u or, u=5-10 or, u=(-5) therefore, object distance is 5 cm to the left side of the mirror. SAY THANKS PLZ....