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In youngs double slit experiment the width of the fringes obtained withy ligh of wavelength 5500 angstrom is 3.9mm. calculate the fringe width if the

entire apparatus is immersed in a liquid medium of refractive index 1.3



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In Young's double slit experiment :

     β = fringe width = λ D / d,
                     D = perpendicular distance between slits and screen
                     λ = wavelength of light source,
                     d = distance between slits

     velocity in vacuum / velocity in liquid = 1.3
       λ  in vacuum * frequency / λ in liquid * frequency  = 1.3
             λ in liquid = 5,500 / 1.3  Angstroms
       β is proportional to λ , as D and d are same.

         β in vacuum / β liquid medium  = λ in vacuum / λ in liquid

             β in liquid =  β in vacuum * λ in liquid / λ in vacuum
                             = 3.9 mm * (5,500 /1.3) Angstrom / (5,500 Angstrom)
                             = 3.9 / 1.3 =  3 mm

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