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A parachutist after bailing out falls 50 m without friction. When parachute opens, it decelerates at

2 m/s2. He reaches the ground with a speed of 3m/s. At what height, did he bail out? (g = 9.81 m s2)


The velocity after he descends 50m is given by u²=2(9.81)50=981.
He reaches ground with speed, v=3m/s with deceleration a=-2m/s².
Then, v²-u²=2(a.s) → s=972/4=243m.
The height at which he bailed out would be h = 243+50 = 293m
2 4 2
dont you think there will be effect of gravity also.
and 'a' in 2nd equation will be different
Yes, a in second equation is -2.
jackie - u need to be a little more explanatory than that. that explanation often is not understood easily
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