Answers

  • Brainly User
2014-12-25T13:04:14+05:30

sin(A)=\frac{1}{\sqrt{2}}A=45^{o}.
Then, tan(A-B)=\frac{1-tanB}{1+tanB}=\frac{1}{\sqrt{3}}.
Then, tanB=2-\sqrt{3}B=15^{o}.

tanA=\frac{a}{b} then sinA=\frac{a}{\sqrt{a^{2}+b^{2}}}.

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