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We have ABCD a cyclic quadrilateral and BC II AD
The sum of opposite angles of cyclic quadrilateral is 180 degree
This gives angle ABC=180-110=70 degree
The triangle ABC has angle ABC=70  and angle BAC=50
           Hence angle BCA=180 - 70 - 50 = 60 degree
 We know BC II AD and angles BCA and DAC are alternate interior angles
 Hence  angle BCA = DAC=60 degree
  Angle DAC=60 degree
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