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When an object is placed at a distance of 60 cm² from a convex theorical mirror , the magnification produced is 1/2. Where should the object be placed to a

magnification of 1/3 ?



In the first part

In case of convex mirror, u= -60cm

m= 1/2 implies v= 30cm(Since image must be virtual)

On substituting in equation, 1/u + 1/v = 1/f

or f = uv/ u+v we get f=60cm

In IInd case, m= 1/3=0.33




Substituting  in f=uv/u+v

we get u= -2f =(-2) x 60 cm= -120 cm

2 4 2
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