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Same force acts on two different masses 3 kg and 5kg initially at rest.The ratio of times required to acquire same final velocity is?



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Initial velocity = u = 0
final velocity = v

v = 0 + at = at = (F/m)t = F*(t/m)

let the velocities be v1=v2=v

 \frac{v_1}{v_2} = \frac{t_1/m_1}{t_2/m_2}  \\  \\ 1= \frac{t_1/3}{t_2/5} \\  \\  \frac{t_1}{3} = \frac{t_2}{5}  \\  \\  \frac{t_1}{t_2} = \frac{3}{5}

So the ratio of times = 3/5

2 4 2
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