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  • Brainly User
2014-12-29T19:02:16+05:30
Kinetic Energy at the instant of throwing, K=\frac{1}{2}mv^{2}=\frac{1}{2}(4)(30)^{2}J=1800J.
Potential Energy at the topmost point, U=1800J.
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but how can potential energy is 1800J
kinetic energy gets converted to potential energy.
2014-12-29T19:30:12+05:30
K.E is = 1800 J
P.E at top= 1800J
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