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A cubical block of ice is completely immersed in water .what is the bouyant force acting on the block if the sidd of the block is 1 cm




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Length of cube = 1cm
volume = 1×1×1 = 1cm³ = 10^-6 m³

when the cube is immersed in water, volume of water displaced = 1cm³ = 10^-6 m³
density of water = 1000kg/m³
weight of displaced water = density×volume×g = 1000×10^-6×9.8 = 9.8×10^-3 N
Since buoyant force is equal to the weight of water displaced, the buoyant force acting is 9.8×10^-3 N
1 5 1
When the cube is immersed in water Volume of water displaced=1cube cm Weight of displaced water=100×10^-6×9.8=9.8×10^-3N
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