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Perimeter of rhombus is 20cm Hence the length of side =20/4= 5 cm Let the Rhombus be ABCD. 1. Draw line using scale and mark AB=5 cm 2. At A draw angle OAB = 70 degree using protractor. 3. Mark point D on AO using compass where AD=5 cm 4. Using D and B as centers draw arcs with radius 5 cm . 5. Let the arcs intersects at C. 6. Join DC and BC to get Rhombus ABCD.

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The cyclical quadrilateral Rhombus has all its sides equal. The angles (opposite) are equal. Adjacent angles are supplementary (sum to 180 deg).

Side = perimeter / 4 = 5 cm

The two different Angles are : 70 deg and 180 - 70 = 110 deg.

1. Draw a line segment AB horizontally of length 5 cm. 2. Draw a line segment (from A) at an angle of 70 deg to AB using a protractor. Measure 5 cm from A on this line and mark it as C. Or, using a compass draw an arc with radius 5 cm with center as A to cut this inclined line at point C.

3. Draw a line segment from B at angle of 110 deg to AB, on the same side as AC.

4. Now using a compass draw an arc with radius 5 cm to cut the inclined line at D.