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The length of seconds pendulum is decreased by 0.3 m when shifted to Chennai from London .if at London ,g=981cm/s²

Find g at Chennai


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The time period of a seconds pendulum = 2s

At London, 
g = 981cm/s² = 9.81 m/s²
find the length.

T=2 \pi \sqrt{ \frac{l}{g} } \\ \\ 2=2 \pi \sqrt{ \frac{l}{9.81} } \\ \\ \frac{1}{ \pi } = \sqrt{ \frac{l}{9.81} } \\ \\ l= \frac{9.81}{ \pi ^{2} } =\frac{9.81}{10}=0.981m

At Chennai,
length is 0.3 cm less or 0.003m less
so l = 0.981-0.003 = 0.978m
g = ?

T=2 \pi \sqrt{ \frac{l}{g} } \\ \\ 2=2 \pi \sqrt{ \frac{0.978}{g} } \\ \\ \frac{1}{ \pi } = \sqrt{ \frac{0.978}{g} } \\ \\ g= 0.978* \pi ^{2} =9.78\ m/s^2=978\ cm/s^2

So The value of g at Chennai is 978 cm/s².
2 5 2
It is given in the question that the length decreased by 0.3m. It is very odd. That will never happen. So i have used 0.3cm instead of 0.3m which is a more probable value.
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