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The length of seconds pendulum is decreased by 0.3 m when shifted to Chennai from London .if at London ,g=981cm/s²

Find g at Chennai

π²=10

1
by Aryendra

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Find g at Chennai

π²=10

by Aryendra

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The time period of a seconds pendulum = 2s

At London,

g = 981cm/s² = 9.81 m/s²

find the length.

At Chennai,

length is 0.3 cm less or 0.003m less

so l = 0.981-0.003 = 0.978m

g = ?

**So The value of g at Chennai is 978 cm/s².**

At London,

g = 981cm/s² = 9.81 m/s²

find the length.

At Chennai,

length is 0.3 cm less or 0.003m less

so l = 0.981-0.003 = 0.978m

g = ?