Answers

2015-01-03T19:05:46+05:30
Plz see the attachment below-
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2015-01-03T19:21:00+05:30
We know that ,
 sin²x + cos²x = 1
⇒ sin²x = 1-cos²x
⇒ sinx = √(1-cos²x)
sinx= \sqrt{1- \frac{1}{ sec^{2}x } }  \\ sinx= \sqrt{  \frac{ sec^{2}x -1}{ sex^{2}x } }  \\
sinx =  \frac{ \sqrt{ sec^{2}x-1 } }{secx}
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