Answers

2015-01-03T22:29:48+05:30
AB=15
BC=18
CO IS THE PERPENDICULAR ON AB.
CO=9
So,Area of parallelogram ABCD =AB*CO
                                               =18*9=162
162=BC*AM
 AM=162/15=10.8
1 4 1
2015-01-06T17:42:41+05:30
Let the height from A to BC be AE.
LET THE HEIGHT FROM C TO AB BE CF
AB=CD=15CM (OPPOSITE SIDES OF A PARALLELOGRAM ARE EQUAL)
BC=AD=18CM (            "       "           " "       "                            "    "        )
AE=9CM
AREA OF PARALLELOGRAM=BASE X PERPENDICULAR HEIGHT FROM BASE
AREA= (18 X 9)CM²= 162CM²
II CASE
ARE OF IIGM=BASE X PERPENDICULAR TO BASE HEIGHT
AREA= (15 X CF)CM²⇒162/15=CF
CF=10.8CM
1 1 1