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Let the points be designated as A(-3,-2); B(3,2); C(-2\sqrt{3},3\sqrt{3}).
Then, we need length of sides, using L=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}
BC=\sqrt{52}, CA=\sqrt{52}, AB=\sqrt{52}.
Hence, BC=CA=AB=\sqrt{52}.
All the sides are equal, therefore vertices A, B, C form an equilateral triangle.
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