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A+1=(a-1)/3-2a. (a+1)(3-2a)=a-1. 3a-2a²+3-2a=a-1. 3a-2a-a-2a²=-1-3. -2a²=-4. -2×2=-4. -4=-4. Lhs =Rhs. Hence proved.
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not good
Is it unclear
I wrote in different lines but still it appears so
I've added a full stop after each step to give the least level of organization
We have a²=2
         ⇒ a²-1= 2-1
         ⇒ (a+1)(a-1) = 1
         ⇒ (a+1) =1/(a-1)
RHS= (a-1)/(3-2a)
       = (a-1)/(2+1-2a)
       = (a-1)/ (a²+1-2a)       as  a²=2
       = (a-1)/(a-1)²
       = 1/(a-1)
       = a+1= LHS
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