# A pentagon has interior angles of measures x ,(x-4),(2x-10),(2x-5) (2x+15). find the measure of each angle

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⇔ x + (x-4) + (2x-10) + (2x-5) + (2x+15) = 540

⇔ 8x - 4 = 540

⇔ 8x = 540+4 = 544

⇔ x = 544/8 = 68

Angles are:

x = 68

x-4 = 68-4 = 64

2x-10 = 2*68 -10 = 136 -10= 126

2x - 5 = 2*68 -5 = 136-5 = 131

2x +15 = 2*68+15 = 136+15 = 151

Angles are 68,64,126,131 and 151. All are in degrees.