Answers

  • Brainly User
2015-01-05T19:00:57+05:30
Sum of interior angles of a pentagon = 540
⇔ x + (x-4) + (2x-10) + (2x-5)  + (2x+15) = 540
⇔ 8x - 4 = 540
⇔ 8x = 540+4 = 544
⇔ x = 544/8 = 68

Angles are:
x = 68
x-4 = 68-4 = 64
2x-10 = 2*68 -10 = 136 -10= 126
2x - 5 = 2*68 -5 = 136-5 = 131
2x +15 = 2*68+15 = 136+15 = 151

Angles are 68,64,126,131 and 151. All are in degrees.
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2015-01-05T21:14:34+05:30
We know that Sum of interior angles of a pentagon is  540 degree
ATQ  x + (x-4) + (2x-10) + (2x-5)  + (2x+15) = 540
   ⇒ 8x - 4 = 540
   ⇒ 8x = 544
   ⇒ x  = 544/8 = 68
So substituting value of x we get angles as
 1. x = 68 degree
 2. x-4 = 68-4 = 64 degree
 3. 2x-10 = 2*68 -10 = 126 degree
 4. 2x - 5 = 2*68 -5 = 131 degree
 5. 2x +15 = 2*68+15 = 151 degree


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