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Prove that the area of a trapezium is half the sum of the parallel sides multiplied by the distance between them

plz i want the answer of the question


Draw a trapezium say abcd and join the diagonals you will obtain two triangle draw two perpendiculars on diagonals from both parallel sides 
now area of quadrilateral(trapezium)=sum of area of both the triangles
        let a and b be two parallel sides and h be the perpendiculars 
area of 1st triangle=1/2 x a  x h  ....1
 area of 2nd triangle=1/2 x b x h .........2
                      sum of 1 and 2 = area of quadrilateral(trapezium)
1/2 x a x h +1/2 x b x h= area of trapezium       
1/2 x (a+b) x h= area of trapezium             (taking out 1/2 as common)

thus proved............

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The formula of trapezium is 1/2*dh
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