Answers

2015-01-07T20:20:30+05:30
Total possible outcome are = (1,1) (1,2) (1,3) .......................(6,6)        (total 36
a) most likely possible total = 6+6 = 12
b) least likely possible total = 1+1 = 2
c) probability of getting total 2 = 1/36
d) total 7 = (1,6) (6,1) (2,5) (5,2) (3,4) (4,3) = 6
probability = 6/36 = 1/6
e) total less than 7 = 2,3,4,5,6 = (1,1) (1,2) (1,3) (1,4) (1,5) (2,1) (2,2) (2,3) (2,4) (3,1) (3,2) (3,3) (4,1) (4,2) = 14
 probability = 14/36 = 7/18
f) total will be an odd number only when one dice contain odd another contain even
(1,2) (1,4) (1,4) (3,2) (3,4) (3,6) (5,2) (5,4) (5,6) (2,1) (2,3) (2,5) (4,1) (4,3) (4,5) (6,1) (6,3) (6,5) 
 so total possible out come = 18
probability = 18/36 = 1/2
g) a prime number from 2 to 12 = 2,3,5,7,11
total getting 2 = (1,1)
total getting 3 = (1,2) (2,1)
total getting 5 = (1,4) (2,3) (3,2) (4,1)
total getting 7 = (1,6) (6,1) (2,5) (5,2) (3,4) (4,3)
total getting 11 = (5,6) (6,5)
probability = 15/36 = 5/12
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