Answers

2015-01-08T19:41:42+05:30
Sin2a=2sin a cos a
then,
2sin a cos a= 2 sin a
2 sin a (cos a -1)=0
then,
sin a = 0, then a= kpi 
(kpi=k integer pi = 3.14159....)
cos a = 1 then, a = 2kpi

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2015-01-08T19:45:15+05:30
Given 
sin2A=2sinA

we know that sin2A=2sinA.cosA

sin2A=2sinA .1
sin2A=2sinA .cos 0° = sin2A=2sinA.cosA

cos 0° = cos A
A=0°
2 4 2