Answers

2015-01-09T10:57:11+05:30
2015-01-09T12:16:39+05:30
Area of square ABCD = 144 sq cm
So, side of square ABCD = 12 cm
Side of the square obtained by joining the midpoints of the ABCD =  \sqrt{ (\frac{side}{2})^2+(\frac{side}{2})^2 }

Therefore, the side of the square PQRS =  \sqrt{ (\frac{12}{2})^2+(\frac{12}{2})^2 } =  \sqrt{72} = 6 \sqrt{2}

Area of square PQRS = (6 \sqrt{2}  )^2 = 72 sq cm

Perimeter = 4 × (6 \sqrt{2}) 24 \sqrt{2} cm
0
It can be done pythogras theorem
Its done using pythagoras theorem only. the third step explains the same