# In a competetive examination,a candidate scores 5 marks for each correct answer and looses 2 marks for every wrong answer.if he attempts 85 question and scores 285 marks,find the number of questions he attempts correctly

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so x + y = 85

5x - 2y = 285

on solving these equations u'll get x = 65

no of questions which are incorrect=

so as per the question

x + y = 85 (1)

5x - 2y = 285(2)

from one y =85-x (3)

by substitution equation 3 in 2 you get

5x-2 (85-x)=285

5x-170+2 x=285

7x=285+170

7x=455

x=65

a