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So the number divisible by 6 , 8 must also be divisible with 24

so the smallest number divisible by 24 is 24 and the highest number is 192

so the number of digits is 192 = 24 + (n-1)24

⇒168/24 + 1 = n

⇒ n = 8 so the

probability of that the integer chosen is divisible by 6 or 8 is 8 / 200 = 1/25 = 0.04

The no.s are divisible by either 6 or 8 If the digits are divisible 6 they are multiples of 6. We have 200/6=33.3 i.e 33 digits which are divisible by 6. Similarly we have 200/8=25 i.e 25 digits divisible by 8. There are some common integer which are also divisible by 6 and 8. We have LCM of 6&8 is 24 So the digits divisible by 24 are both divsisible by 6 & 8. 200/24= 8.3 i.e 8 digits are divisible by 6 and 8 We have no. of digits divisible either by 6 or 8 = 33+25-8=50 hence the probability is 50/200 i.e 1/4