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Area of trapezium=1/2 x (sum of parallel sides) x height 1/2 x (16+10) x 6=1/2 x 16 x 6=78 sq.cm In the case of rhombus the area is 1/2 x diagonal₁ x diagonal₂ But in the figure the second diagonal is not give so we have to find it out. We know that the diagonals of a rhombus bisect each other at right angle. First we have to bisect the diagonal which has length of 16cm into 8 cm. By using Pythagoras theorem H²=P²+B² 10²=8²+B² 100=64+B² 100-64=B² 36=B² 6=B THEREFORE SECOND DIAGONAL=2B=2 X 6=12CM area of rhombus=1/2*16*12=96cm² area of trapezium₂=1/2*(10+20)*8 1/2*30*8=120cm² Area of the figure=(120+96+78)=294cm₂ So the answer is (4) 294cm²