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An express train travelled at an average speed of 100km/hr stopping for 3 minutes after travelling 75km/hr local train travelling at a speed of 50km/hr

stop for 1minute after every 25km. if both the trains start at the same time,how many km did the local time travel in the time in which the express train in which the express train travel in the time in which the express train travelled 600km?

Express train
For travelling 75 km--time--75/100*60=45 min
48 min-----75 km
1 km ------48/75 min
600 km ---48/75*600 min
=384 mins
Local train travels for 384 mins
speed- 50kmph
stops for 1 min after 25 one
25kms ----31 mins
Nearest multiple of 31 is 372
In 372 mins ----- 372/31*25 kms
=300 ins
In the remaining (384-372) 12 mins or 1/5 hrs
distance traveled=speed *time
=1/5*50
=10 km
therefore final answer is 310 kms

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Express speed 100 km/hr stops for 3 min = 1/20 hours after every 75 km.

local train speed 50 kmph stops for 1 min after every 25 km Local train travels 25 km in 25 / 50 = 1/2 hour = 30 min Include halt, it travels 25 km in 31 minutes.

express express travels 75 km in : 75/100 = 3/4 hour = 45 min include halt = 48 min. express travels 75 km in 48 minutes. so it travels 600 km in 600 * 48 / 75 = 24 * 16 = 384 minutes

Local in 384 minutes, it travels 384 / 31 * 25 km = 390.677 km