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1.the perimeter of sector of a circle whose central angle is 90 and radius is 7cm is

2.a thin wire is in the shape of circle of radius 77cm.is bent into a square the side of square is 3.angle in major segment is 4.sum of angles in pentagon is 5. if A is an acute angle of ABC triangle right angled at B then value of sinA+cosA is

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Perimeter = Ф R, where Ф = central angle of sector of circle in radians Perimeter for central angle of 90 deg = π/2 * R = 22 / 7 * 1/2 * 7 cm = 11 cm ======== length of wire = perimeter of circle = 2π *77 = 484 cm perimeter of square = 4 * side = 484 cm side = 121 cm ====================== Angle made by a side of regular pentagon at the center = 360 / 5 = 72 deg Sum of the two equal base angles at the side = 180 - 72 = 108 deg. Hence, Internal angle at one vertex = 108 deg. Sum of all 5 internal angles of pentagon = 540 deg. Formula = π [ n - 2 ] ====================

A = acute B = 90 deg C = acute angle Sin A + Cos A = Sin A + Cos (180 - 90 - C) = Sin A + Sin C = 2 Sin (A+C)/2 Cos (A-C)/2 = 2 SIn 45 Cos (A-C)/2 = √2 Cos (A-C)/2

Or, simply Sin A + Cos A = opposite side / hypotenuse + adjacent side / hypotenuse = (AB + BC) / AC

==== square that => [ AB² + BC² + 2 AB BC ] / AC² = 1 + 2 AB * BC / AC² so answer = square root of that.