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Let x be a let 1/x be b Therfore a*b=1 a+b=3 (a+b)^3=a^3+b^3+3ab(a+b) a^3+b^3=(a+b)^3-3ab(a+b) a^3+b^3=3^3-3*3{substituting the values} a^3+b^3=27-9=18 now, a^3=x^3 b^3=1/x^3 therefore, x³ + 1/x³=18
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