Answers

2014-04-08T18:10:24+05:30
Given,
initial velocity(u)=0
final velocity(v)=36km/hr=36*5/18(m/s)=10m/s
time(t)=10 min=600 sec
distance(s)=?
from 1st equation of motion,
v=u+at
10=a(600)
a=10/600
a=0.16m/(s^2)
from second equation of motion,
s=ut+1/2*a*(t^2)
  =0+1/2(0.16)[(600)^2]
  =28800m
  =28.8km
therefore,distance=28.8 km
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  • Brainly User
2014-04-09T19:59:31+05:30
U=0
v=36 km/hr=36 X 5/18=10 m/sec 
t=10 min=600 sec
v=u+at
a=10/600 = 1/60 m/sec²
s=ut+1/2at²
 = 1/2 X 1/60 X 600 X 600
 = 30000mts
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