Do pick the best one out ! :)

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length of rect. = 2m

breadth of rect. = 1.4m

ar. of rectangle =length × breadth = 2 × 1.4 = 2.8 m²

Diameter of the circle = 1.4m D= radius÷2, r = 0.7 m

Area of a circle = πr²

= (22/7) × (0.7)²

= 1.54 m²

totle ar. of figur = Area of the rectangle + Area of the two semicircles

= 1.54+2.8 =**4.34 m²**

breadth of rect. = 1.4m

ar. of rectangle =length × breadth = 2 × 1.4 = 2.8 m²

Diameter of the circle = 1.4m D= radius÷2, r = 0.7 m

Area of a circle = πr²

= (22/7) × (0.7)²

= 1.54 m²

totle ar. of figur = Area of the rectangle + Area of the two semicircles

= 1.54+2.8 =

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

In the given figure, there is a rectangle and two semicircles.

Length of the rectangle(l) = 2m

Breadth of the rectangle(b) = 1.4m

Area of a rectangle = l × b

= 2 × 1.4 = 2.8 m²

There are two semicircles of equal diameter and hence, we can consider them as a single circle.

Diameter of the circle = 1.4m ⇒ radius, r = 0.7 m

Area of a circle = πr²

= (22/7) × (0.7)² (Consider the value of π as 22/7)

= 1.54 m²

**Total area of the figure** = Area of the rectangle + Area of the circle

= 2.8 + 1.54

=**4.34 m²**

Length of the rectangle(l) = 2m

Breadth of the rectangle(b) = 1.4m

Area of a rectangle = l × b

= 2 × 1.4 = 2.8 m²

There are two semicircles of equal diameter and hence, we can consider them as a single circle.

Diameter of the circle = 1.4m ⇒ radius, r = 0.7 m

Area of a circle = πr²

= (22/7) × (0.7)² (Consider the value of π as 22/7)

= 1.54 m²

= 2.8 + 1.54

=