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If x≤-1   then,
                       x²+x+1=x(x+1)+1≥1            since x and x+1  are both negative                           if -1 smaller than x smaller than 0  , then                                                               x²+x+1=x²+(x+1) greater than 0+0=0                                                             thus in other words convert it in form                                                                                                (d x+e)²+f=0
0 0 0
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