Answers

2015-01-18T23:54:00+05:30
6x+py=5
6x+py-5=0
ax+by+c=0; here a=6, b=p, c=-5
3x+4y=2
3x+4y-2=0
here a=3, b=4, c=-2
if they have no solution then a1/a2=b1/b2≠c1/c2
then substitute the values
we get 6/3=p/4≠-5/-2
the value of p is 8
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2015-01-19T16:16:17+05:30
If two equations ax+by=c and px + qy = r has no solution then 
 \frac{a}{p} =  \frac{b}{q}

6/3 = p/4
2 = p/4
p = 8
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