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1.log a^(xy)=log a^x+log a^y
Let log a^x be p and log a^y be q
p=log a^x                        x=a^p
q=log a^y                         y=a^q
log a^xy=p+q
log a^xy=log a^x+log a^y
2.log a^m^n=nlog a^m
p=log a^m^n
log a^m=p/n
p=nlog a^m
log a^m^n=nlog a^m
3.almost the same as the second prove
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