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A bag contains 7 blue,8 red, 6 green and 5 yellow balls. a ball is drawn from the bag at random. find the probability of getting (i) a green ball (ii) a

yellow ball (iii) a white ball (iv) a blue ball .
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1. 6/7+8+6+5 = 6/26 = 3/13
2. 5/26
3. 0/26 = 0. because there are no white balls
4. 7/26
1 5 1
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1)a green ball=6/26=3/13
2)A yellow ball=5/26

0 0 0
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