# A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:

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Let the present age of son = x years then present age of man will be x+24 years

After 2 years, Age of son = x+2 years and age of man= x+24+2 yrs =x+6 years

According to given condition, x+26 = 2(x+2)

x+26= 2x+4

x=22 present age of his son =22 years and his father's present age=x+24= 46years