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A cube of edge 9cm is immersed completely in rectangular vessel containing water. If the dimensions of base are 15 cm ×12m , find the rise in water level

in vessel.


Let the increase in height = h
volume of cube = volume of water risen
⇒9³ = 15*12*h
⇒ h = 9³/(15*12) 
⇒ h = 4.05 cm -------rise in water level
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We know that vol. of the water displaced=vol. of the object immersed
here,  vol. of the obj.=9³=729
given,the base of the vessel=15cm*12m
so,the vol. of the displaced water=15*1200*h(converting m into cm)
729=18000h so, h=0.0405cm
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