Answers

2015-01-22T20:25:41+05:30


Let 13a & 13b be the two numbers

13a*13b =2028

ab =12

(1,12) & (3,4) are the co prime no with product 12

Hence required numbers are (13*1, 13*12) & (13*3 , 13*4) So there are 2 such pairs


1 4 1