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One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 36 minutes, then the slower pipe alone will be

able to fill the tank in:



Let x minutes be the time taken by the slower pipe alone to fill the tank then the faster pipe will fill the tank in x/3 minutes

Acc 2 Q, 1/x + 3/x = 1/36

4/x = 1/36 ⇒x =144

Therefore, the slower pipe alone will fill the tank in 144 minutes

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