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Two resistors of same length have ratio of their cross-section area 1:2 .Resistors are made of same material.Which resistor has more resistance and how



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Resistor R1......c.s.a-x (cross sectional area) Resistor R2......c.s.a-2x Resistance is in inversely proportional to square of cross section area. Let constant used be k. Therfore R1=k(1/x^2)..... R2=k(1/{2x}^2)=k(1/4x^2)...R1/R2=k(1/x^2)/ k(1/4x^2)=4/1 or 4:1(ans)
1 5 1
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