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The answer is 6. as if we add 6+5+2we get 13 and if we add 3+6+4 we get 13
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A number is divisible by 11, if the difference of sum of digits in the odd places and the sum of digits in even places is either 0 or divisible by 11.
sum of digits in odd places = k+5+2 = k+7
sum of digits in even places = 3+6+4 = 13

So k+7 = 13
or k = 13-7 = 6
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u are considering the case of 0, why no take the case if the difference is 11??
for that case, (k+7)-13 = 11(minimum) or k-6 = 11 or k =17
k is a single digit number..not a two digit one...
you can't place 17 in place of k as k is a single digit
got it, thnx
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