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12 workers can complete a piece of work in 10 days . If the number of workers will be reduced to 1/3 rd of the original number. then how manu more days

would be requird to complete the same work


No. of workers                                         days
12                                   -                      10
1/3 rd of original workers    -                       x     =        4        -         x

days to work with 4 workers(x)=12×10/4
required days =>  30-10=20
therefore 20 more days would be required.

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Number of workers=12
number of days=10
1/3rd of workers =4
it is a case of inverse variation
so 12×10=4×x
so 30 more days are required.
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