Answers

2015-01-28T15:23:38+05:30

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Mirror is situated at a distance of 30cm from the image.(according to your question). If you want more, then it is given below...

Assuming that a real image is formed, 
magnification = -2
image distance = -30 cm
object distance = u

m = - \frac{v}{u}\\ \\-2= -(\frac{-30}{u} ) \\  \\ -2= \frac{30}{u}\\ \\u= \frac{30}{-2}\\ \\u =\boxed{-15cm}

Using mirror formula;

 \frac{1}{f} =  \frac{1}{u}+ \frac{1}{v}  = \frac{1}{-15}+ \frac{1}{-30} = \frac{-2-1}{30} \\ \\ \frac{1}{f}= \frac{-3}{30}\\ \\ f= \frac{30}{-3}=\boxed {-10cm}
2 4 2