Log in to add a comment

Log in to add a comment

The Brainliest Answer!

given:- in triangle ABC is the right triangle right angled at B.

RTP:- AC^2 = AB^2+ BC^2

Construction:- Draw BD perpendicular to AC.

Proof:- triangle ADB similar to triangle ABC

AD/AB = ab/AC

AD*AC*=AB^2 .................. (1)

also triangle BDC similar to triangle ABC

AC/BC = BC/AC

CD*AC=bc^2 ................. (2)

on adding 1 and 2

AD*AC+CD*AC=AB^2+BC^2

AC(AD+CD)=AB^2+BC^2

AC*AC=AB^2+BC^2

AC^2=AB^2+BC^2