Answers

2015-01-29T09:32:55+05:30
In IBr2  No. of valence electrons = 7+(2*7)+1 = 22
Noble gas compound having 22 electrons is XeF2 = 8 +(2*7) = 22
IBr2 is isostructural  with XeF2 and both are linear in shape .
1 5 1