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To prove:AB+BC+AC>2AD Consider triangle ABD,AB+BD>AD.......(i) Consider triangle ADC, AC+CD>AD.......(ii) (i)+(ii)=› AB+AC+BD+DC>2AD [BD+DC=BC] So, AB+BC+BC>2AD Hence proved.
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Thanks Aayushi99.
Pls. Mark as the best!!!
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