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A field is in the shape of a square with side 20m. a pathway of 2m width is surrounding it. find the outer perimeter of the pathway



Side of inner square = 20 m Side of outer square = (20+2) x (20+2) = 22 x 22 = 484 m
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Perimeter of square =4 x side therefore Perimeter =4x20=80m Width of path=2m Now each side of square becomes 24m. Now the Perimeter becomes 4x24 =96m
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