Answers

2015-02-02T15:32:40+05:30

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
When the bomb is dropped, it will have an initial horizontal velocity which is equal to the speed of the aeroplane. So the bomb fall and travel forward too.

initial horizontal velocity,v_x = 600 km/h
v_x=600\ km/h = 600* \frac{5}{18}\ m/s=166.67\ m/s
initial vertical velocity,v_y = 0
height, h = 1960m
time taken to fall = t

h=v_yt+ \frac{1}{2}gt^2\\ \\1960=0+ \frac{1}{2}*9.8*t^2\\ \\1960=4.9t^2\\ \\t^2= \frac{1960}{4.9}=400\\ \\t= \sqrt{400}=20s

In 20s, the horizontal distance travelled is AB

AB=v_x*t=166.67*20=\boxed{3333.4\ m}
3 4 3