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Let the initial length of side = a Area, A = a²

increase in length = 200% 200% of a = final length, a' = a + 2a = 3a Area, A' = (3a)² = 9a²

Increase in area = 9a² - a² = 8a² % increase = × 100 = 8×100 = 800%

Let original side be x ten area of square=s^2=x^2 let new side be x + 200% of x= x+2x=3x area of new square=(3x)^2=9x² increase=9x²-x²=8x² increase %=(increase/original area)*100%=(8x²/x²*100)%=800 Therefore the area of the new square will increase by a)800