Answers

2015-02-03T16:26:04+05:30

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Radius of small sphere (r) = 0.25cm
radius of large sphere (R) = 4 cm
let the total number of small sphere formed = n

n*volume\ of\ small\ sphere=volume\ of\ large\ sphere\\ \\n* \frac{4}{3} \pi r^3 =\frac{4}{3} \pi R^3 \\ \\n*r^3=R^3\\ \\n= \frac{R^3}{r^3}= (\frac{R}{r})^3  \\ \\n=(\frac{4}{0.25})^3=16^3\\ \\n=\boxed{4096}
0
2015-02-03T17:17:35+05:30
Volume of big sphere=4/3*pi*R*R*R
4/3*22/7*64
no.of spheres*volume of 1 small sphere=volume of big sphere
let the no.of sphere be y
y(4/3*22/7*0.25*0.25*0.25)=4/3*22/7*64
4/3 and 22/7 on both sides get cancelled
y=64/0.015625
y=4096
therefore, no.of spheres are 4096
0