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A hemispherical basin 150 cm in diameter holds water 120 times as much as a cylindrical cube.if height of the tube is 15 cm,then diameter of the tube is




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V_{hemisphere}=120*V_{cylinder}\\ \\ \frac{2}{3} \pi r_h^3=120* \pi r_c^2h\\ \\ \frac{2}{3}r_h^3=120* r_c^2h\\ \\ \frac{2}{3}*75^3=120* r_c^2*15\\ \\ r_c^2= \frac{2*75^3}{3*120*15} \\ \\r_c=  \sqrt{\frac{2*75^3}{3*120*15} }=12.5\ cm\\ \\diameter=2r_c=2*12.5=\boxed{25\ cm}
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I think the answer would be25
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